Find the volume of oxygen required to burn zinc with a mass of 65 grams.

m (Zn) = 65 g.

Let’s determine the volume of oxygen that has reacted. We write down the solution.

We write down the equation of reactions.

2Zn + O2 = 2ZnO.

Find the amount of zinc. We use the following formula.

n = m / M.

Where n is the amount of substance.

m is the mass of the substance.

M is the molar mass of the substance.

M (Zn) = 65.4 g / mol.

n = 65 / 65.4 = 0.99 mol.

Let us determine the amount of oxygen substance according to the reaction equation.

0.99 mol Zn – x mol О2

2 mol Zn – 1 mol О2

X = 0.99 * 1: 2 = 0.495 mol.

Next, we determine the volume of oxygen.

n = V / Vm.

V = n * Vm = 0.495 mol * 22.4 l / mol = 11.088 l.

Answer: V (O2) = 11.088 liters.