Find the volume of oxygen that is needed for the combustion of phosphorus with a mass of 155 g

Find the volume of oxygen that is needed for the combustion of phosphorus with a mass of 155 g. The combustion product is phosphorus oxide.

The synthesis reaction of phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 phosphorus atoms interact with 5 oxygen molecules. In this case, 2 molecules of phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance in phosphorus weighing 155 grams.

M P = 31 grams / mol;

N P = 155/31 = 5 mol;

To burn such an amount of phosphorus, 5 x 5/4 = 6.25 mol of oxygen will be required.

Let’s calculate its volume.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

The required volume of oxygen will be:

V O2 = 6.25 x 22.4 = 140 liters;