Find the volume of pentene (C5H10), the combustion of which consumed 90 liters of oxygen.
| December 19, 2020 | education
Given: V (O2) = 90L
Find: V (C5H10) -?
Decision.
Let us write down the equation of pentene combustion: 2C5H10 + 15O2 => 10CO2 + 10H2O n = V / Vm Vm = 22.4 mol / L n (O2) = 90 / 22.4 = 4.018 mol Find the amount of pentene by the stoichiometric ratio: 2 – x 15 – 4.018 x = 0.54 mol V = Vm * n V (C5H10) = 22.4 * 0.54 = 12.096 L
Answer: 12.096 liters.
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