Find the volume of propene (C3H6), if 144 g of oxygen were consumed for its combustion.

In accordance with the condition of the problem, we compose the equation:
2С3Н6 + 9О2 = 6СО2 + 6Н2О – propene combustion reaction, carbon dioxide and water are released;
M (C3H6) = 42 g / mol; M (O2) = 32 g / mol;
Let us determine the amount of molar oxygen, if the mass is known:
Y (O2) = m / M = 144/32 = 4.5 mol.
Let’s make the proportion:
X mol (C3H6) – 4.5 mol (O2);
-2 mol -9 mol from here, X mol (C3H6) = 2 * 4.5 / 9 = 1 mol.
Let’s calculate the volume of propene:
V (C3H6) = 1 * 22.4 = 22.4 liters.
Answer: The reaction will require 22.4 liters of propene.