Find the volume of sulfur oxide so3 that is formed during the combustion of 20 liters of so2 2so2 + o2 = 2so3.

2SO2 + O2 = 2SO3
Let’s find the amount of SO2: n = V / Vm, where Vm = 22.4 l / mol – molar volume, constant for all gases.
V (SO2) = 20 L / 22.4 L / mol = 0.89 mol.
According to the reaction from 2 mol of SO2, 2 mol of SO3 is formed, that is, n (SO2) = n (SO3) = 0.89 mol.
Find the volume: V (SO3) = n * Vm = 0.89 mol * 22.4 l / mol = 19.936 l.
Answer: The volume of SO3 is 19.936 liters.

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