Find the volume of the body obtained by rotation about the Ox axis of the function y = x ^ 2 and x = 0, x = 3.

The volume of a body of revolution, if the dependence of the change in its cross-sectional area is known, is determined by the formula:

V = integral (a to b) f (x) dx.

Because the area of the spherical section is pi * R², then we get the function:

f (x) = pi * R² = pi * (x²) ² = pi * x4.

Therefore, the volume of the body of revolution will be equal to:

V = integral (from 0 to 3) pi * x4 dx = pi * x ^ 5/5 (from 0 to 3) = pi * 3 ^ 5/5 = 48.6 * pi units ³.

Answer: the volume of the body is 48.6 * pi units ³.



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