Find the volume of water with t = 20 C, during the crystallization of which the same amount

Find the volume of water with t = 20 C, during the crystallization of which the same amount of heat is released as with the complete combustion of gasoline m = 1.0 kg.

Initial data: tн (initial water temperature) = 20 ºС; m2 (mass of gasoline) = 1 kg.

Constants: tк (crystallization temperature) = 0 ºС; C (specific heat) = 4200 J / (kg * K); λ (specific heat of crystallization) = 34 * 10 ^ 4 J / kg; q (specific heat of combustion of gasoline) = 4.6 * 10 ^ 7 J / kg.

С * m1 * (tк – tн) + λ * m1 = q * m2 = m1 * (С * (tк – tн) + λ).

m1 = q * m2 / (C * (tc – tn) + λ) = 4.6 * 10 ^ 7 * 1 / (4200 * (20 – 0) + 34 * 10 ^ 4) = 108.49 kg (density water 1000 kg / m ^ 3 and V = 108.49 l).