Find the volume that will take: a) 8g О₂ b) 192kg ozone c) 12 * 10²⁰ molecules N₂
| March 31, 2021 | education
a) (8 g / 32 g / mol) * 22.4 L = 0.25 * 22.4 L = 5.6 L O2.
b) (192 kg / 48 g) * 22.4 L = 4000 * 22.4 L = 89600 L O3.
c) (12 * 10 ^ 20/6 * 10 ^ 23) * 22.4 L = 0.002 * 22.4 = 0.0448 L = 44.8 ml of nitrogen.
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