Find the water pressure on the bottom of a cylindrical vessel with a base area of 50 cm2 into which 2

Find the water pressure on the bottom of a cylindrical vessel with a base area of 50 cm2 into which 2 liters of water have been poured.

S = 50 square centimeters = 0.005 square meters – the bottom area of a cylindrical vessel;

V = 2 liters = 0.002 cubic meters – the volume of water poured into the vessel;

ro = 1000 kg / m ^ 3 – water density;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine P (Pascal) – water pressure at the bottom of the vessel.

Find the height of the water column in the vessel:

h = V / S = 0.002 / 0.005 = 0.4 meters.

Then the pressure on the bottom will be equal to:

P = ro * g * h = 1000 * 10 * 0.4 = 4000 Pascal (4 kPa).

Answer: the pressure on the bottom of the vessel is 4 kPa.