Find the work performed by a field with a strength of 126 kV / M when a 2nC charge moves at a distance of 2 cm.

To calculate the work done by the field in question, we will use the formula: A = U / q = E * d / q.

Values of variables: E – the intensity of the considered field (E = 126 kV / m = 126 * 10 ^ 3 V / m); d – charge movement (d = 2 cm = 0.02 m); q is the amount of charge (q = 2 nC = 2 * 10 ^ -9 C).

Let’s perform the calculation: A = E * d / q = 126 * 10 ^ 3 * 0.02 * 2 * 10 ^ -9 = 5.04 * 10 ^ -6 J = 5.04 μJ.

Answer: The field in question performed work at 5.04 μJ.