# Find the yield of carbon dioxide during the decomposition of calcium carbonate m = 500 g

**Find the yield of carbon dioxide during the decomposition of calcium carbonate m = 500 g, impurity 10%, if it is known that the gas yield is 85% of the theoretically possible.**

The decomposition reaction of calcium carbonate when heated is described by the following chemical equation:

CaCO3 = CaO + CO2 ↑;

Let’s calculate the chemical amount of calcium carbonate. To do this, we divide its weight by the mass of 1 mole of the substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 500 x 0.9 / 100 = 4.5 mol;

Taking into account the reaction yield of 85%, 4.5 x 0.85 = 3.825 mol of carbon dioxide will be synthesized.

To calculate its volume, you need to multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V CO2 = 3.825 x 22.4 = 85.68 liters;