Find two consecutive natural numbers whose product is 132.

Let’s say one of these numbers is x.

By the condition of the problem, the numbers are natural and sequential, so the second number will be equal to x + 1.

We get the following equation:

x * (x + 1) = 132,

x ^ 2 + x = 132,

x ^ 2 + x – 132 = 0.

Let’s solve this quadratic equation. Let’s find the discriminant:

D = 1 ^ 2 – 4 * 1 * (-132),

D = 1 + 528,

D = 529, therefore √529 = 23.

Thus, we get:

x = (- 1 – 23) / 2 = -12 and x = (-1 + 23) / 2 = 11.

By condition, the numbers are natural, which means they will look like:

11 and 11 + 1 = 12.

Answer: 11 and 12.