Find V of carbon dioxide which is released during the decomposition of 17.2 g of CuCO3.

1. Let us write down the decomposition equation for copper carbonate:

CuCO3 = CuO + CO2 ↑;

2.Calculate the chemical amount of carbonate:

n (CuCO3) = m (CuCO3): M (CuCO3);

M (CuCO3) = 64 + 12 + 3 * 16 = 124 g / mol;

n (CuCO3) = 17.2: 124 = 0.1387 mol;

3. Determine the amount of emitted carbon dioxide:

n (CO2) = n (CuCO3) = 0.1387 mol;

V (CO2) = n (CO2) * Vm = 0.1387 * 22.4 = 3.1 liters.

Answer: 3.1 liters.