Finish the ORP equations indicate the oxidation reduction and the type of ORP K2CrO4

Finish the ORP equations indicate the oxidation reduction and the type of ORP K2CrO4 + (NH4) 2S + H2O = Cr (OH) 3 + S + KOH + NH4OH

2K2CrO4 + 3 (NH4) 2S + 8H2O = 2Cr (OH) 3 + 3S + 4KOH + 6NH4OH – potassium chromate reacts with ammonium sulfide and water to form chromium hydroxide, sulfur, potassium hydroxide and ammonium hydroxide.
Cr (6+) + 2 e = Cr (3+)
S (2-) – 2e = S (0)
K2CrO4 – chromium oxidizing agent;
(NH4) 2S – sulfur reducing agent.



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