Finish the reaction and arrange the coefficients: O3 + FeSO4 + H2SO4 =

Finish the reaction and arrange the coefficients: O3 + FeSO4 + H2SO4 = Fe2 (SO4) 3 + H2O.
This is only what happened in this example, but in order for it to be correct, it must be equalized.
So we look that there are 2 atoms on the right side of Ferum, so we put the number 2 on the left side, but since SO4 is three atoms, then we need to make a paired coefficient. We put 3 on the right side, and on the left it means we need to put – 6. Now we count the hydrogen and oxygen atoms and set the coefficients, it turned out like this:
O3 + 6 FeSO4 + 3 H2SO4 = 3 Fe2 (SO4) 3 + 3 H2O