Fission of one nucleus of the isotope of uranium 235 releases 200 MeV of energy.

Fission of one nucleus of the isotope of uranium 235 releases 200 MeV of energy. Determine the amount of energy released by fission of 20 kg of uranium.

Given:

fission of isotopic uranium 235 occurs.

w1 = 200 MeV.

m = 20 kg.

To find:

W -? amount of energy.

Let’s start by remembering the formula:

N = m / m0, where

m = M / Na, where

m is the mass, kg;

M – molar mass, mol.

Na is Avogadro’s number, 6.022 140 76 * 10 ^ 23 mol − 1.

Substitute the values and perform the calculation:

N = m / m0 = (m * Na) / M = (20 * 6 * 10 ^ 23) / 235 * 10 ^ -3 = 85 * 10 ^ 23.

To calculate the amount of energy released during the fission of 20 kg of uranium 235, we use the formula:

W = N * w1 = 85 * 10 ^ 23 * 200 = 17 * 10 ^ 26 MeV.