For 1 hour at a constant current, a charge of 180 C was transferred. Determine the amperage.

Given:

t = 1 hour – time interval;

q = 180 Coulomb – the charge that was transferred over a period of time t.

It is required to determine I (Ampere) – current strength.

Let’s convert the units of measurement of time to the SI system:

t = 1 hour = 1 * 60 = 60 minutes = 60 * 60 = 3600 seconds.

Then, to determine the current strength, you must use the following formula:

q = I * t, from here we find that:

I = q / t = 180/3600 = 18/360 = 0.05 Amperes (50 milliamperes).

Answer: The current strength is 0.05 Amperes (50 milliamperes).