For 20 minutes, an electric charge of 960Kl passes through the iron. determine the amperage in the iron.

Initial data: t (duration of the iron) = 20 min; q (charge that passed through the iron) = 960 Cl.

SI system: t = 20 min = 20 * 60 = 1200 s.

The current in the iron can be determined by dividing the amount of electric charge by the operating time of the iron: I = q / t.

Let’s carry out the calculations: I = 960/1200 = 0.8 A.

Answer: The current in the iron is 0.8 A.