For 4 s, the body moving uniformly accelerated without initial speed has covered the path of 32 m

For 4 s, the body moving uniformly accelerated without initial speed has covered the path of 32 m. What is the speed at the end of the path?

Given:

L = 32 meters – the path taken by a body moving at uniform acceleration;

t = 4 seconds – the period of time during which some body passed the path L.

It is required to determine v (meter per second) – the speed of the body at the end of the path.

Since, according to the condition of the problem, the body began to move without initial velocity (v0 = 0), we find the acceleration:

L = v0 * t + a * t ^ 2/2;

L = a * t2 / 2;

a = 2 * L / t ^ 2 = 2 * 32/4 ^ 2 = 2 * 32/16 = 2 * 2 = 4 m / s2.

Then the speed of the body at the end of the path will be equal to:

v = v0 + a * t;

v = a * t;

v = 4 * 4 = 16 meters per second.

Answer: the speed of the body at the end of the path will be 16 meters per second.