# For a rectangle, one of the sides is 3 9 / 10cm, and the other is 2 3/5 times smaller.

For a rectangle, one of the sides is 3 9 / 10cm, and the other is 2 3/5 times smaller. Find the perimeter and area of the rectangle.

Find the value of the unknown side of the rectangle.

Divide 3 9/10 cm by the difference, which, according to the problem, is 2 3/5.

Will be:

3 9/10 / 2 3/5 = 39/10 / 13/5 = 39/10 * 5/13 = 3/2 = 1 1/2 cm.

Find the area of the rectangle.

We multiply the 2 sides of the figure together.

3 9/10 * 1 1/2 = 39/10 * 3/2 = 117/20 = 5 17/20 cm2

We find the perimeter.

Multiply the sum of the first and second sides by 2.

2 * (3 9/10 + 1 1/2) = 2 * (39/10 + 3/2) = 2 * (39/10 + 15/10) = 54/10 * 2 = 108/10 = 10 8 / 10 = 10 4/5 cm.

Answer: Perimeter 10 4/5 cm, area 5 17/20 cm2

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