For a time interval t = 3.0, s, the light manages to travel a distance equal to n = 15 equators

For a time interval t = 3.0, s, the light manages to travel a distance equal to n = 15 equators of some planet. Find the radius R of this planet

The distance that light travels in 3 s can be calculated using the formulas:
S = C * t, where C is the speed of propagation of light in vacuum (C = 3 * 10 ^ 8 m / s), t is the time of movement of light (t = 3 s).
S = 15L, where L is the length of the planet’s equator.
The equator length (circumference) will be equal to: L = 2Π * R.
Then:
C * t = 15L = 15 * 2Π * R = 30Π * R.
Let’s express and calculate the radius of the planet:
R = C * t / (30Π) = (3 * 10 ^ 8) * 3 / (30 * 3.14) = 9554140 m.
Answer: The radius of the planet is 9554140 m.