For a triangle ABC AB = 7 cm BC = 4 cm angle b = 120 gadus find the area of the triangle.

Since the two sides of the triangle and the angle between them are known, the area is equal to half the product of the two sides by the sine of the angle between them.

Formula: S = (1/2) AB * BC * sinb

sin120 = sin60 = √3 / 2

S = (1/2) 7 * 4 * (√3 / 2) = (28/2) * (√3 / 2) = 14 * (√3 / 2) = 7√3

Answer: 7√3



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