For complete combustion of 10 liters of methane according to the reaction CH4 + 2O2 = CO2 + 2H2O, … liters of air is required

In this task, we will determine how much air will be required to burn 10 liters of methane. We write down the solution to this problem.

First, we write down the reaction equation for the combustion of methane.

CH4 + 2O2 = CO2 + 2H2O.

Using the reaction equation, we determine the volume of air.

10 liters of methane – x liters of air.

22.4 l / mol of methane – 2 * 22.4 l / mol of air.

Using the reaction equation, we find the unknown value of x. We write down the solution.

x = 10 * 2 * 22.4 / 22.4 = 20 liters of air.

Therefore, in order to burn 10 liters of methane, 20 liters of air are required.

Answer: 10 liters of air will be required.