For etching hydrochloric acid, 26 g of zinc were consumed. How many liters of hydrogen were released?

Metallic zinc interacts with hydrochloric (hydrochloric) acid with the release of hydrogen gas and the formation of zinc chloride:

Zn + 2HCl = ZnCl2 + H2;

1 mole of zinc reacts with 2 moles of acid. In this case, 1 mol of salt is formed and 1 mol of hydrogen gas is released.

Let’s calculate the available chemical amount of zinc. To do this, divide the weight of pure metal by the weight of 1 mole of metallic zinc.

M Zn = 65 grams / mol;

N Zn = 26/65 = 0.4 mol;

The same amount of hydrogen and zinc chloride salt will be synthesized.

Let’s calculate the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas, which is 22.4 liters.

N H2 = 0.4 mol;

V H2 = 0.4 x 22.4 = 8.96 liters;

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