For evaporation at the boiling point, 180,000 J were required. What is the mass of alcohol evaporated?

univerkov | November 29, 2020 | education

We need a formula:
Q = Lm
L-constant, this is the specific heat of vaporization. L of alcohol is 0.9 × 10 ^ 6 J / kg. Let’s convert 180,000 J to 1.8 × 10 ^ 5 J for an easier calculation. We substitute.
m = Q / L = 1.8 × 10 ^ 5/0, 9 × 10 ^ 6 = 2/10 = 0.2 (kg)

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