For every 15 breaths that a person takes in 1 minute, air with a volume of 600 cm3 enters his lungs

For every 15 breaths that a person takes in 1 minute, air with a volume of 600 cm3 enters his lungs. Calculate the mass of air passing through a person’s lungs in an hour?

t1 = 1 min.

N1 = 15.

V1 = 600 cm3 = 0.0006 m3.

t = 1 h = 60 min.

ρ = 1.29 kg / m3.

m -?

We express the mass of air m by the formula: m = ρ * V, where ρ is the air density, V is the volume of air that passes through the lungs of a person during t = 1 hour.

At t = 1 hour, 60 minutes, and during the time t1 = 1 min, the volume of air V1 passes through his lungs, which means that during the time t = 1 hour the volume V = 60 * V1 passes.

The air mass will be determined by the formula: m = ρ * 60 * V1.

m = 1.29 kg / m3 * 60 * 0.0006 m3 = 0.04644 kg.

Answer: m = 0.04644 kg of air passes through the lungs of a person during t = 1 hour.



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