# For heating a concrete slab weighing 200 kg. from a temperature of 10 s to 40 s, 5.3 MJ

For heating a concrete slab weighing 200 kg. from a temperature of 10 s to 40 s, 5.3 MJ was required. Find the specific heat of concrete

Initial data: m (mass of a concrete slab) = 200 kg; t0 (temperature of the concrete slab before heating) = 10 ºС; t (temperature of the concrete slab after heating) = 40 ºС; Q (required amount of energy) = 5.3 MJ = 5.3 * 10 ^ 6 J.

We express the specific heat of concrete from the following formula:

Q = C * m * (t – t0); C = Q / (m * (t – t0)).

Let’s do the calculation:

C = 5.3 * 10 ^ 6 / (200 * (40 – 10)) = 833.3 J / (kg * K).

Answer: According to the calculation, the specific heat capacity of concrete is 833.3 J / (kg * K).

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