For heating parts weighing 500 g from 10 degrees to 90 degrees it took 15.2 kJ of heat.

For heating parts weighing 500 g from 10 degrees to 90 degrees it took 15.2 kJ of heat. Determine the specific heat of the substance.

Given: m (mass of a given part) = 500 g (in SI m = 0.5 kg); t0 (part temperature before heating) = 10 ºС; t (final temperature) = 90 ºС; Q (heat consumption) = 15.2 kJ (15.2 * 10 ^ 3 J).

To determine the desired heat capacity of the substance from which the given part is made, we use the formula: Q = Cx * m * (t – t0), whence Cx = Q / (m * (t – t0)).

Calculation: Cx = 15.2 * 10 ^ 3 / (0.5 * (90 – 10)) = 380 J / (kg * K).

Answer: A given part is made of a substance with a specific heat of 380 J / (kg * K).