For how many natural values of A are the roots of the equation. ax = 20 are natural numbers.

Let us solve this equation for the unknown x.

Since the number a is natural, we can divide both sides of this equation by this number.

After completing this action, we get:

ax / a = 20 / a;

x = 20 / a.

The root of this equation 20 / a will be a natural number when the number a is a divisor of the number 20.

Let’s list all the divisors of the number 20:

1, 2, 4, 5, 10, 20.

Therefore, the root of the equation ax = 20 is a natural number for six values of the parameter a: a = 1, a = 2, a = 5, a = 10 and a = 20.

Answer: for six values of the parameter a.



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