For the first 50 m, the tram moved at a speed of 5 m-s, and the next 500 m at a speed of 10 m-s.

For the first 50 m, the tram moved at a speed of 5 m-s, and the next 500 m at a speed of 10 m-s. Determine the average speed of the tram along the entire route.

V Wed = S (all distance) / t (all time)
50 + 500 = 550 m – all the way
50/5 = 10 m / s – speed in the first section
500/10 = 50 m / s – speed in the second section
V Wed = 550 / (10 + 50) = 550/60 = 9.16 m / s
Answer: V cf. = 9.16 m / s



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