For the operation of a heat engine with an efficiency of 16%, oil weighing 5.4 tons is stored.

For the operation of a heat engine with an efficiency of 16%, oil weighing 5.4 tons is stored. Determine how many days the fuel supply will last, if the average engine power during operation is 15 kW, a working day is 8 hours.

Data: η (motor efficiency) = 16% (0.16); m (mass of stored oil) = 5.4 tons (5.4 * 10 ^ 3 kg); N (average power of the heat engine during operation) = 15 kW (15 * 10 ^ 3 W); t (length of the working day) = 8 hours (8 * 3600 s).

Reference values: q (specific heat of combustion of oil) = 4.4 * 107 J / kg.

The duration of the use of oil reserves is determined from the formula: η = N * t * n / (q * m), whence n = η * q * m / (N * t).

Calculation: n = 0.16 * 4.4 * 10 ^ 7 * 5.4 * 10 ^ 3 / (15 * 10 ^ 3 * 8 * 3600) = 88 days.