For what period of time a body freely falling without initial velocity has passed 2m. How far has it traveled in the first 4?

Data: S (distance that a given body must travel) = 2 m; t1 (considered duration of the fall) = 4 s; the fall of the given body is free.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Time for a given body to pass the first 2 m: S = g * t ^ 2/2, whence t = √ (2S / g) = √ (2 * 2/10) = 0.632 s.

2) Distance covered in the first 4 s: S = H = g * t1 ^ 2/2 = 10 * 42/2 = 80 m.

Answer: The given body passed the first 2 m in 0.632 s; in the first 4 from the fall, it will pass 80 m.