Force 200n deforms the spring by 5.4 find the potential energy of the spring.
| September 18, 2021 | education
Initial data: F (force that deforms the spring) = 200 N; Δl (spring deformation value) = 5.4 cm = 0.054 m.
1) Calculate the coefficient of spring stiffness:
F = F = k * Δl.
k = F / Δl = 200 / 0.054 = 3704 N / m.
2) Determine the potential energy of the deformed spring:
Ep = k * Δl ^ 2/2 = 3704 * 0.054 ^ 2/2 = 5.4 J.
Answer: The potential energy of the spring is 5.4 J.
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