Forces, modules of which F1 = 8H and F2 = 40H, are balanced on the lever.

Forces, modules of which F1 = 8H and F2 = 40H, are balanced on the lever. Moreover, their moments are equal to 20 N * m. What are the shoulders of these forces?

Task data: F1 (module of the first force) = 8 N; F2 (modulus of the second force) = 40 N; the given forces are balanced on the lever; M (moment of specified forces) = M1 = M2 = 20 N * m.

1) Let’s define the shoulder of the first force: M = F1 * x1 and x1 = M / F1 = 20/8 = 2.5 m.

2) Define the shoulder of the second force: M = F2 * x2 and x2 = M / F2 = 20/40 = 0.5 m.

Answer: The shoulder of the first force is 2.5 m; the second – 0.5 m.