Four substances are given: sulfur (VI) oxide, water, concentrated sulfuric acid, and potassium iodide.

Four substances are given: sulfur (VI) oxide, water, concentrated sulfuric acid, and potassium iodide. Write the equations of four possible reactions between all the proposed substances, without repeating pairs of reagents.

We are presented with four chemicals in the task: tetravalent sulfur oxide, water, concentrated sulfuric acid and potassium iodide salt. Consider the equations of chemical reactions that are possible between them.

The first reaction is the interaction of hexavalent sulfur oxide and water. We get sulfuric acid as a result of a chemical reaction. The molecular equation of the reaction can be written as follows:

SO3 + H2O = H2SO4,

The second chemical reaction is the interaction of hexavalent sulfur oxide and potassium iodide salt. Formed after passing through a chemical reaction, pure iodine, tetravalent sulfur oxide and potassium sulfate salt. Graphically, this equation of a chemical reaction can be expressed as follows:

2 SO3 + 2 KI = I2 + SO2 + K2SO4.