From 140 kg of calcium oxide during the interaction of H2O, 182 kg of CaOH were obtained

| January 14, 2021 | education

From 140 kg of calcium oxide during the interaction of H2O, 182 kg of CaOH were obtained, determine the yield from the theoretical possible.

Let’s execute the solution:
1. We compose the equation according to the condition of the problem:
m = 140 kg. m = 182 kg; W -?
CaO + H2O = Ca (OH) 2 – compounds, calcium hydroxide was obtained;
2. Calculations:
M (CaO) = 56 g / mol;
M Ca (OH) 2 = 74 g / mol;
m (CaO) = 140 kg. = 140,000 g.
m Ca (OH) 2 = 182 kg. = 182000 g.
3. Determine the amount of the original substance:
Y (CaO) = m / M = 140,000 / 56 = 2500 mol.
Y Ca (OH) 2 = 2500 mol since the amount of substances is 1 mol.
4. Find the mass and product yield:
m Ca (OH) 2 = Y * M = 2500 * 74 = 185000 g.
W = m (practical) / m (theoretical) * 100;
W = 182,000 / 185,000 * 100 = 98.38%.
Answer: the yield of calcium hydroxide is 98.38%.



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