# From 140 kg of calcium oxide during the interaction of H2O, 182 kg of CaOH were obtained

**From 140 kg of calcium oxide during the interaction of H2O, 182 kg of CaOH were obtained, determine the yield from the theoretical possible.**

Let’s execute the solution:

1. We compose the equation according to the condition of the problem:

m = 140 kg. m = 182 kg; W -?

CaO + H2O = Ca (OH) 2 – compounds, calcium hydroxide was obtained;

2. Calculations:

M (CaO) = 56 g / mol;

M Ca (OH) 2 = 74 g / mol;

m (CaO) = 140 kg. = 140,000 g.

m Ca (OH) 2 = 182 kg. = 182000 g.

3. Determine the amount of the original substance:

Y (CaO) = m / M = 140,000 / 56 = 2500 mol.

Y Ca (OH) 2 = 2500 mol since the amount of substances is 1 mol.

4. Find the mass and product yield:

m Ca (OH) 2 = Y * M = 2500 * 74 = 185000 g.

W = m (practical) / m (theoretical) * 100;

W = 182,000 / 185,000 * 100 = 98.38%.

Answer: the yield of calcium hydroxide is 98.38%.