# From 140 kg of calcium oxide during the interaction of H2O, 182 kg of CaOH were obtained

From 140 kg of calcium oxide during the interaction of H2O, 182 kg of CaOH were obtained, determine the yield from the theoretical possible.

Let’s execute the solution:
1. We compose the equation according to the condition of the problem:
m = 140 kg. m = 182 kg; W -?
CaO + H2O = Ca (OH) 2 – compounds, calcium hydroxide was obtained;
2. Calculations:
M (CaO) = 56 g / mol;
M Ca (OH) 2 = 74 g / mol;
m (CaO) = 140 kg. = 140,000 g.
m Ca (OH) 2 = 182 kg. = 182000 g.
3. Determine the amount of the original substance:
Y (CaO) = m / M = 140,000 / 56 = 2500 mol.
Y Ca (OH) 2 = 2500 mol since the amount of substances is 1 mol.
4. Find the mass and product yield:
m Ca (OH) 2 = Y * M = 2500 * 74 = 185000 g.
W = m (practical) / m (theoretical) * 100;
W = 182,000 / 185,000 * 100 = 98.38%.
Answer: the yield of calcium hydroxide is 98.38%.

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