From 15 g of nitrobenzene, 8 g of aniline was obtained. Determine the mass fraction of the reaction product yield.

To solve the problem, let’s compose the reaction equation:
C6H5NO2 + 3H2 = C6H5NH2 + 2H2O – aniline was obtained;
M (C6H5NO2) = 123 g / mol;
M (C6H5NH2) = 93 g / mol;
Determine the amount of mol of nitrobenzene:
Y (C6H5NO2) = m / M = 15/123 = 0.122 mol;
According to the reaction equation, the amounts of moles of nitrobenzene and aniline are equal to 1 mole, which means that Y (C6H5NH2) = 0.122 mole;
Let us calculate the theoretical mass of aniline:
m (C6H5NH2) = Y * M = 0.122 * 93 = 11.34 g;
Let’s make the calculations:
W = m (practical) / m (theoretical) * 100;
W = 8 / 11.34 * 100 = 70.55%.
Answer: the mass fraction of the output of aniline is 70.55%.