From 18 g of glucose during alcoholic fermentation, 9 g of ethanol were obtained. Calculate the mass fraction
| December 3, 2020 | education
From 18 g of glucose during alcoholic fermentation, 9 g of ethanol were obtained. Calculate the mass fraction of the theoretical yield of the reaction product.
C6H12O6 = 2C2H5OH + 2CO2
n (C6H12O6) = m \ M = 18 \ 180 = 0.1 mol
for ur-th p-i n (C2H5OH) = 0.1 * 2 = 0.2 mol
m (C2H5OH) theory = n * M = 0.2 * 46 = 9.2 g
output = m (practical) \ m (theory) = 9 \ 9.2 = 0.98 (98%)
Answer: 98%
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