From 200 g of technical calcium carbide, 60 liters of acetylene were obtained. What is the percentage
From 200 g of technical calcium carbide, 60 liters of acetylene were obtained. What is the percentage of pure carbide in a technical sample?
Let’s calculate the theoretical volume of acetylene.
The reaction for the synthesis of acetylene from calcium carbide is described by the following chemical reaction equation:
CaC2 + 2H2O = C2H2 + Ca (OH) 2;
From 1 mole of calcium carbide, 1 mole of acetylene is synthesized.
Let’s calculate the available chemical amount of silicon carbide substance.
M CaC2 = 40 + 12 x 2 = 64 grams / mol;
N CaC2 = 200/64 = 3.125 mol;
The same amount of acetylene will be synthesized.
Let’s calculate its volume. To do this, multiply the amount of substance in mol by the standard volume of 1 mol of gaseous substance, which is 22.4 liters.
V C2H2 = 3.125 x 22.4 = 70 liters;
The content of pure carbide in a technical sample is 60/70 = 0.857 = 85.7%;
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