From 34.5 g of ethanol, 11.2 liters of ethylene were obtained. Calculate the volume fraction

From 34.5 g of ethanol, 11.2 liters of ethylene were obtained. Calculate the volume fraction of the reaction product yield.

According to the condition of the problem, we compose the reaction equation:
С2Н5ОН = Н2О + С2Н4 – dehydration reaction, ethylene was obtained;
M (C2H5OH) = 46 g / mol;
M (C2H4) = 28 g / mol;
Determine the amount of moles of ethanol, if the mass is known:
Y (C2H5OH) = m / M = 34.5 / 46 = 0.75 mol;
According to the reaction equation, the number of moles of ethanol and ethylene are equal to – 1 mol, which means that Y (C2H4) = 0.75 mol;
Find the theoretical volume of ethylene:
V (C2H4) = 0.75 * 22.4 = 16.8 liters.
Let’s calculate the volume fraction of ethylene yield: V (practical) / V (theoretical) * 100 = 11.2 / 16.8 * 100 = 66.67%.
Answer: The volume fraction of ethylene yield is 66.67%.



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