From 390 g of benzene, 410 g of phenol was obtained in two stages. determine the mass fraction

From 390 g of benzene, 410 g of phenol was obtained in two stages. determine the mass fraction of the reaction product yield from the theoretically possible

1. We make a chemical equation, not forgetting to put down the coefficients:

C6H6 = C6H5OH.

2. Let’s find the amount of substance C6H6:

n (C6H6) = m (C6H6) / M (C6H6) = 390/78 = 5 mol.

3. From the equation you can see:

n (C6H6) = n (C6H5OH) = 5 mol.

4. Find the mass of C6H5OH:

m (C6H5OH) = n (C6H5OH) * M (C6H5OH) = 5 * 94 = 470g.

5. Find the mass fraction of the output:

ω = m (practical) (C6H5OH) * m (theoretical) (C6H5OH) = 410/470 = 0.87 (87%).

Answer: ω = 87%.