From 5.4 g aluminum, 7.14 g of alumina were obtained. Determine the yield of aluminum oxide from the theoretically possible.
| March 2, 2021 | education
The reaction equation for the production of aluminum oxide:
4Al + 3O2 = 2Al2O3.
Let us find the theoretical mass of the oxide:
Mr (Al) = 27 * 4 = 108 g / mol.
Mr (Al2O3) = 2 * 102 = 204 g / mol.
m (Al2O3) = 5.4 * 204/108 = 10.2 g.
Let’s determine the output of aluminum oxide from the theoretically possible:
W (Al2O3) = mpr * 100% / mtheor. = 7.14 * 100 / 10.2 = 70%.
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