From 50 g of nitrogen containing 5% impurities, received ammonia, calculate the mass of the obtained ammonia?

Let’s implement the solution:
1. In accordance with the condition of the problem, we write down the process:
m = 50 g. 5% – impurities X g -?
N2 + 3H2 = 2NH3 – compounds, ammonia was obtained;
2. Calculations:
M (N2) = 28 g / mol;
M (NH3) = 17 g / mol.
3. Determine the mass of the original substance without impurities, the amount:
m (N2) = 50 * (1 – 0.5) = 25 g;
Y (N2) = m / M = 25/28 = 0.89 mol.
5. Proportion:
0.89 mol (N2) – X mol (NH3);
-1 mol – 2 mol from here, X mol (NH3) = 0.89 * 2/1 = 1.78 mol.
6. Find the mass of the product:
m (NH3) = Y * M = 1.78 * 17 = 30.26 g.
Answer: received ammonia weighing 30.26 g.