From 500 g of a 45% sulfuric acid solution, 200 g of water was removed by evaporation.

From 500 g of a 45% sulfuric acid solution, 200 g of water was removed by evaporation. Determine the mass fraction of sulfuric acid in the remaining solution.

Decision:
1.m (H2SO4) = 400 * 0.5 = 200g;
(m – the resulting solution); (H2SO4) = 400-100 = 300g;
w (H2SO4) = 200/300 = 66.6%.
Answer: 66.6%.



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