From 6.2 g of phosphorus, you can get calcium phosphide weighing …

Given:
m (P) = 6.2 g

To find:
m (Ca3P2) -?

Decision:
1) 2P + 3Ca => Ca3P2;
2) n (P) = m (P) / M (P) = 6.2 / 31 = 0.2 mol;
3) n (Ca3P2) = n (P) / 2 = 0.2 / 2 = 0.1 mol;
4) m (Ca3P2) = n (Ca3P2) * M (Ca3P2) = 0.1 * 182 = 18.2 g.



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