From 80 g of a 60% solution of formic acid and the required amount of methyl alcohol, 43.8 g

From 80 g of a 60% solution of formic acid and the required amount of methyl alcohol, 43.8 g of methyl formic ester were obtained. Determine the mass fraction of the product yield.

1. Let’s compose the reaction equation for obtaining methyl formate:

HCOOH + CH3OH → HCOOCH3 + H2O;

2.Calculate the mass of formic acid:

m (HCOOH) = w (HCOOH) * m (solution) = 0.6 * 80 = 48 g;

3.Calculate the chemical amount of acid:

n (HCOOH) = m (HCOOH): M (HCOOH);

M (HCOOH) = 1 + 12 + 32 + 1 = 46 g / mol;

n (HCOOH) = 48: 46 = 1.0435 mol;

4.determine the theoretical amount of ester:

ntheor (HCOOCH3) = n (HCOOH) = 1.0435 mol;

5.Let’s find the theoretical mass of the ether:

mtheor (HCOOCH3) = ntheor (HCOOCH3) * M (HCOOCH3);

M (HCOOCH3) = 1 + 12 + 32 + 12 + 3 = 60 g / mol;

mtheor (HCOOCH3) = 1.0435 * 60 = 62.61 g;

6.Calculate the mass fraction of the product yield:

ν (HCOOCH3) = mpract (HCOOCH3): mtheor (HCOOCH3) = 43.8: 62.61 = 0.6996 or 69.96%.

Answer: 69.96%.