From a certain height above the surface of the earth, a body is thrown vertically downward

From a certain height above the surface of the earth, a body is thrown vertically downward with an initial speed of 5 m / s. In 5 from its fall, the body will fly a path?

To find the path that the abandoned body flew in 5 seconds, we will use the formula: S = V0 * t + a * t ^ 2/2 = V0 * t + g * t ^ 2/2.

Variables and constants: V0 – body speed after throw (V0 = 5 m / s); t is the duration of the fall (t = 5 s); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: S = V0 * t + g * t ^ 2/2 = 5 * 5 + 10 * 5 ^ 2/2 = 150 m.

Answer: In 5 seconds from its fall, the thrown body will cover a distance of 150 m.