From a dam with a height of 22 m, 500 tons of water falls in 10 minutes. How much power does it develop?

Initial data: h (dam height) = 22 m; t (duration of water fall from the dam) = 10 min (600 s); m (mass of water that fell from the dam) = 500 tons (500 * 10 ^ 3 kg).

Reference values: g (acceleration due to gravity) = 9.81 m / s2.

The power that develops when water falls from the dam is determined by the formula: N = A / t = ΔEp / t = m * g * h / t.

Let’s make the calculation: N = 500 * 10 ^ 3 * 9.81 * 22/600 = 179 850 W ≈ 180 kW.

Answer: When water falls from the dam, a power of 180 kW is developed.