From a dam with a height of 22 s, 500 tons of water falls in 10 minutes. How much power does it develop?

To find out the power obtained due to the fall of 500 tons of water from the dam, we use the formula: N = A / t = ΔEп / t = m * g * Δh / t.
Const: q – free fall acceleration (q = 9.81 m / s2).
Data: m is the mass of the fallen water (m = 500 t = 5 * 10 ^ 5 kg); Δh – change in water height, dam height (Δh = 22 m); t – elapsed time (t = 10 min = 6 * 10 ^ 2 s).
Calculation: N = m * g * Δh / t = 5 * 10 ^ 5 * 9.81 * 22 / (6 * 102) = 179.85 * 103 W = 179.85 kW.
Answer: When 500 tons of water fall, a power of 179.85 kW should develop.