From a depth of 5 meters, a stone with a volume of 0.6 m3 is raised to the surface of the water.

From a depth of 5 meters, a stone with a volume of 0.6 m3 is raised to the surface of the water. The density of the stone substance is 2500 kg / m3. What work has been done while lifting the stone?

Given:

h = 5 meters – the depth at which the stone lies;

V = 0.6 m ^ 3 – volume of the stone;

ro = 2500 kg / m ^ 3 is the density of the stone;

ro1 = 1000 kg / m ^ 3 – water density;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine A (Joule) – work when lifting a stone.

Let’s find the weight of the stone in the water:

P = P1 – Aarchimedes = m * g – ro1 * V * g = ro * V * g – ro1 * V * g =

= V * g * (ro – ro1) = 0.6 * 10 * (2500 – 1000) = 6 * 1500 = 9000 Newtons.

This means that in order to lift a stone, you need to apply a force equal to P.

Then:

A = F * h = P * h = 9000 * 5 = 45000 Joules.

Answer: 45,000 Joules were done to lift the stone.